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[单选题]
函数z=ln(x2+y2-2)+
函数z=ln(x2+y2-2)+
的定义域为( )
A.x2+y2≠2
B.x2+y2≠4
C.x2+y2≥2
D.2<x2+y2≤4
查看答案
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A.x2+y2≠2
B.x2+y2≠4
C.x2+y2≥2
D.2<x2+y2≤4
函数f(x)=lnx- ln(x-1)的定义域是()
A.(-1,+∞)
B.(0,+∞)
C.(1,+∞)
D.(0,1)
设函数z=f(x,y)的定义域为D={(x,y)|0≤x≤1,0≤y≤1},则函数f(x^2,y^3)的定义域为()
A.{(x,y)|0≤x≤1,0≤y≤1}
B.{(x,y)|-1≤x≤1,0≤y≤1}
C.{(x,y)|0≤x≤1,-1≤y≤1}
D.{(x,y)|-1≤x≤1,-1≤y≤1}