题目内容
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[单选题]
一正弦交流电的有效值为10A,频率为50HZ,初相位为30,则其解析表达式为()。
A.i=10sin(314t+30)A
B.i=10sin(314t-30)A
C.i=14.1sin(314t+30)A
D.i=14.1sin(314t-30)A
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A.i=10sin(314t+30)A
B.i=10sin(314t-30)A
C.i=14.1sin(314t+30)A
D.i=14.1sin(314t-30)A
A.i=10√2Sin(50t+30°)A
B.i=10Sin(314t-30°)A
C.i=10√2Sin(314t-30°)A
D.i=10Sin(314t+30°)A
A.u=20sin(50t+30°)V
B.u=20sin(314t+30°)V
C.u=28.28sin(50t+30°)V
D.u=28.28sin(314t+30°)V