![](https://static.youtibao.com/asksite/comm/h5/images/m_q_title.png)
[单选题]
用0.1mol的氯化钠固体配成溶液500mL,所得溶液的物质的量浓度为()
A.0.1mol/L
B.0.2mol/L
C.0.3mol/L
D.0.4mol/L
![](https://static.youtibao.com/asksite/comm/h5/images/m_q_a.png)
B、0.2mol/L
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)
A.0.1mol/L
B.0.2mol/L
C.0.3mol/L
D.0.4mol/L
B、0.2mol/L
A.3.12
B.31.2
C.312
D.3120
A.电子天平无须归零,即用来称取氯化钠固体
B.称量时可将氯化钠固体直接放在托盘上
C.量取水时,用规格为50 mL的量筒
D.把配制好的氯化钠溶液倒入刚用蒸馏水润洗过的试剂瓶中,并贴上标签
A.5%,0.1mol/L
B.10%,0.1mol/L
C.5%,0.01mol/L
D.10%,0.01mol/L
水的K1=1.86K·kg·mol-1)
(1) 0.1mol·kg-1蔗糖的水溶液; (2) 0.1mol·kg-1乙二醇的水溶液;
(3) 0.1mol·kg-1乙二醇的苯溶液; (4) 0.1mol·kg-1氯化钠水溶液。
A.1mol/L
B.2mol/L
C.0.1mol/L
D.0.01mol/ml